Find the Closest Element in BST

-
https://practice.geeksforgeeks.org/problems/find-the-closest-element-in-bst/1/

Input:
        10
      /   \
     2    11
   /  \ 
  1    5
      /  \
     3    6
      \
       4
K = 13
Output: 2
Explanation: K=13. The node that has
value nearest to K is 11. so the answer
is 2

class Solution
{
public:
    void helper(Node *root, int &mn_dif, int &k)
    {
        if (root = NULL)
            return;
        mn_dif = min(mn_dif, abs(root->data - k));
        if (root->data > k)
            helper(root->left, mn_dif, k);
        else if (root->data < k)
            helper(root->right, mn_dif, k);
        else
            return;
    }
    int minDiff(Node *root, int K)
    {
        int mn_dif = INT_MAX;
        helper(root, mn_dif, K);
        return mn_dif;
    }
};

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